Home WAEC NECO NABTEB
JAMB CBT JUPEB IJMB Other Exams Main Website
Want To Contact Us? Click Here

Quick Contact

Click To Send Us SMS Now
Click To Chat Examrelief On WhatsApp

Latest WAEC on Giditrends

2018 JAN/FEB WAEC GCE Chemistry Practical Answers/Expo/Dubs/Runz
WAEC February 1, 2018 • 3 years ago • No Comment Yet

2018 JAN/FEB WAEC GCE Chemistry Practical Answers, 2018 JAN/FEB WAEC GCE Chemistry Practical Expo, 2018 JAN/FEB WAEC GCE Chemistry Practical Runz, 2018 JAN/FEB WAEC GCE Chemistry Practical Questions & Answers, 2018 JAN/FEB WAEC GCE Chemistry Practical choke, JAN/FEB WAEC GCE Chemistry Practical Expo, JAN/FEB WAEC GCE Chemistry Practical Runz, JAN/FEB WAEC GCE Chemistry Practical Chock, complete JAN/FEB WAEC GCE Chemistry Practical Expo, verified JAN/FEB WAEC GCE Chemistry Practical Runz, correct JAN/FEB WAEC GCE Chemistry Practical Chock, WAEC First Series Chemistry Alt Practical, WAEC First Series Chemistry Practical Expo, WAEC First Series Chemistry Practical Runz, WAEC First Series Chemistry Practical Questions & Answers, Free WAEC First Series Chemistry Practical Answers, 2018 WAEC First Series Chemistry Practical Expo, Free 2018 JAN/FEB WAEC GCE Chemistry Practical Runz, Free 2018 JAN/FEB WAEC GCE Chemistry Practical Questions & Answers, free 2018 JAN/FEB WAEC GCE Chemistry Practical choke

ATTENTION:- ALWAYS SUBSCRIBE IF YOU NEED EARLY ANSWERS.

? 2018 JAN/FEB WAEC CHEMISTRY PRACTICAL  ANSWERS?

100% VERIFIED CHEMISTRY PRACTICAL  ANSWERS
1. CLICK HERE
(1ai)
Burrette readings/cm3:|titre 1|titre2|titre3
Final readings |33.20 |49.60 |1.50
Initial readings |16.40 |16.40 |16.65
(1aii)
Average volume of acid used
= 16.40+16.40+16.65(cm3)/3
=49.45cm3/3
=16.48cm3
(1b)
(I) Concentration of Y(OH)2.XH2O in mol/dm3
Using CAVA/CBVB = a/b
CA= 0.025mol/0.25dm3 = 0.1mol
VA = 16.48cm3
CB = ?
VB = 25.00cm3
a = 1mol
b = 2 moles
.:. CAVA/CBVB =a/b
CB = CAVA*B/VB*a
= 0.1 mol/dm3 * 16.48cm3 * 2 moles / 25.00 * 1 mol
CB = 3.296/25
CB = 0.131mol/dm3
================================
2. CLICK HERE
2 )
Test
I . Solution + NaOH in excess
Ii . Solution + NH 3 in excess
Iii . Solution + BaCl + HCl in excess
Iv. Solution + AgNO 3
Observation
I . White gelatinous precipitate soluble in excess NaOH
Ii . White gelatinous precipitate soluble in excess NH 3
Iii . White precipitate formed with BaCl2 which dissolves in excess HCl
iv . White precipitate formed with AgNO 3
(2bi)
The reagent is the aliphatic monocarboxylic acids that contains one carboxyl group per molecule
[CnH2n+1COOH]
(2bii)
It is observed that they are called fatty acids due to some of them are found in natural fats and oil by changing the -e- ending the corresponding alkane to -oic acid
Pls Draw a table: for Ethanedioic acid(Oxalic acid), Cis-butenedioic(Maleic acid) & 2,3 dihydroxybutanedioic acid(tartaric acid)
Under Ethanedioic acid(Oxalic acid):
COOH
|
CooH
Under Cis-butenedioic(Maleic acid):
H-C-COOH
||
H-C-COOH
Under 2,3 dihydroxybutanedioic acid(tartaric acid):
H
|
HO-C-COOH
|
HO-C-COOH
|
H
====================================
3a)
I)Desiccator- usefor preserving moisture sensitive items
ii)Volumetric flasks are used for precise dilutions and preparation of standard solutions.
iii)Glass rod are used to mix chemicals and liquids for laboratory purposes .
3ii)
i)Amphoteric is Al2O3
ii)Neutral oxide is H2O
3iii)
Crystallization
3b.
i. hno3aq to cuco3 solid. a light blue solid,
precipitates is formed
ii. acidified kmno4 to c2h4. c2h4 is oxidized to ethane-1,2-
diol
iii. iodine solution to a paste of unripe plantain. a bluish-black color is produced with iodine

=====COMPLETED=====

Don’t Just Copy Alone, Drop your Comments, Share with your friends on Facebook, Twitter And Google+ Using the below share buttons and like our Facebook fan pages Here and Here
BEST OF LUCK

Click Here To Comment
Main Acts:

Leave a Reply